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How to rationalise the planar structre of I2Cl6?

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$\ce{I2Cl6}$ is a dimer of $\ce{ICl3}$. $\ce{ICl3}$ is T-shaped, with $\ce{I}$ being $\mathrm{sp^3d}$ and having two lone pairs.

I read in Inorganic Reaction Mechanisms by R. K. Sharma that $\ce{I2Cl6}$ is formed by the extra two $\ce{Cl-I}$ bridge bonds. What I don't understand is, why does the bridge bond form? And is it a coordinate bond or something like a banana bond (as in $\ce{B2H6}$)?

Source: Sharma, R. K. Inorganic Reaction Mechanisms; Discovery Publishing House: 2007.


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